4x^2+80x+144=0

Solution for 4x^2+80x+144=0 equation:

4x^2+80x+144=0

a = 4; b = 80; c = +144;
Δ = b2-4ac
Δ = 802-4·4·144
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-64}{2*4}=\frac{-144}{8}
=-18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+64}{2*4}=\frac{-16}{8}
=-2
$